What ios domain range

Finding area and vary besides the usage of a graph
It's constantly a lot easier to work out the area and range when analyzing it off the diagram (but we need to make sure we zoom in and out of the layout to make sure we see the whole thing we need to see). However, we don't usually have get admission to to graphing software, and sketching a plan typically requires knowing about discontinuities and so on first anyway.

As meantioned earlier, the key things to check for are:

There are no bad values underneath a square root sign
There are no zero values in the denominator (bottom) of a fraction
Example 3
Find the domain and range of the function \displaystyle f{{\left({x}\right)}}=\frac{\sqrt{{{x}+{2}}}}{{{x}^{2}-{9}}},f(x)=
x
2
−9
x+2



, without the usage of a graph.
Solution
In the numerator (top) of this fraction, we have a rectangular root. To make sure the values under the square root are non-negative, we can only pick \displaystyle{x}x-values grater than or equal to -2.

The denominator (bottom) has \displaystyle{x}^{2}-{9}x
2
−9, which we recognise we can write as \displaystyle{\left({x}+{3}\right)}{\left({x}-{3}\right)}(x+3)(x−3). So our values for \displaystyle{x}x can't encompass \displaystyle-{3}−3 (from the first bracket) or \displaystyle{3}3 (from the second).

We do not need to worry about the \displaystyle-{3}−3 anyway, because we dcided in the first step that \displaystyle{x}\ge-{2}x≥−2.

So the area for this case is \displaystyle{x}\ge-{2},{x}\ne{3}x≥−2,x≠3, which we can write as \displaystyle{\left[-{2},{3}\right)}\cup{\left({3},\infty\right)}[−2,3)∪(3,∞).

To work out the range, we reflect onconsideration on pinnacle and backside of the fraction separately.

Numerator: If \displaystyle{x}=-{2}x=−2, the pinnacle has price \displaystyle\sqrt{{{2}+{2}}}=\sqrt{{{0}}}={0}
2+2

=
0

=0. As \displaystyle{x}x will increase cost from \displaystyle-{2}−2, the top will additionally increase (out to infinity in each cases).

Denominator: We spoil this up into four portions: 






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